Show IP
Display visitor’s IP Address in a graphic with this simple php code.
(Please do not link to this image, it is for demonstration only.)
create a new page, copy the text below and save it as image.php (or whatever you wish)
All you’ll need to display on other pages is the code below.
<img src=”http://yoursitehere.com/image.php” border=”1″>
note: this code will only on systems that support GD image tools
Thank you for this code. How can a background image be used?
I got it
$img_number = imagecreate(110,24);
$image = imagecreatefromgif(‘image.gif’);
$backcolor = imagecolorallocate($img_number,254,46,212);
$textcolor = imagecolorallocate($image, 0, 0, 0);
imagefill($image,0,0,$backcolor);
$number = $user['position'];
Imagestring($image,9,26,4,$number,$textcolor);
header("Content-Type: image/gif");
imagegif($image);
ImageDestroy($image);
Would it be best if you used: if(!empty($_SERVER['HTTP_CLIENT_IP']))
{
$ip = $_SERVER['HTTP_CLIENT_IP'];
}
elseif(!empty($_SERVER['HTTP_X_FORWARDED_FOR']))
{
$ip = $_SERVER['HTTP_X_FORWARDED_FOR'];
}
else
{
$ip = $_SERVER['REMOTE_ADDR'];
}
To get the ip??
thank for this script ^_^
Hi,
I want to find out who and which IP addresses are clicking on my web site in order to block click fraud and solicitors.
Can you help me?
Thanks
Richard
That information is best obtained from your server logs.
nice script.
thanks 4 share.
Thank you so much guys.
I’m loving this.
Hi every one my name is AlAa
My problem with $_SERVER['remote_addr']
I’m not sure if I’m having a problem with the installation of PHP on the server or if there’s something that I’m not doing right in the code, but I am trying to capture the IP address of anyone that is trying to log into a secure part of a site. Regardless of my IP address, when I do:
Code:
echo $_SERVER['remote_addr'];
It returns ’192.168.1.1′. This is the first time I’ve written code that is being used on a Windows Server, so I don’t know if that has anything to do with it.
I’ve run phpinfo(), and in the PHP Variables section, it shows “_SERVER["REMOTE_ADDR"]” : 192.168.1.1. Does this mean that the php.ini file is setup wrong, or am I missing something?
i am running my own server on windows 7 iis7.5 with php as fastcgi and i am behind a router with a dynamic ip not static and i am using
http://www.no-ip.com/ that give me a link to my router and i am opening 80 port in my router forwarding it to my id address 192.168.1.5 and i have tested a php file that contains
tested it using tor network that give me ip out of my network to test that file always give me the same result 192.168.1.1 i am trying to get IP address of the visitor and i asked someone of my friends to use this form it sends the same ip
i hope someone tells me what i am doing wrong and the solution for this problem
Thanks in advance
allscoop,
thanks for the scripts
AlAa YoSeF
this will happen if you check your scripts from your LAN
try to go home and call your server scripts from home
FYI ($_SERVER[REMOTE_ADDR]“;) is not to show the server ip
its to show the client public IP
regards
Routers/MY
Just put this on your page where you want it.
” YOUR IP IS: ”
Php code is really confusing.. but thanks you make me easy to understand
Thanks.. i like it